Counting the Number of Even and Odd Elements in an Array in Python

Understanding Even and Odd Count

This task involves counting the number of even and odd elements in an array.

We will explore three different methods to achieve this in Python.

Method 1: Using Loop

This method iterates through the array and counts even and odd elements.

def count_even_odd(arr):
    even_count = sum(1 for num in arr if num % 2 == 0)
    odd_count = len(arr) - even_count
    print(f"Even Count: {even_count}, Odd Count: {odd_count}")

arr = [1, 2, 3, 4, 5, 6, 7, 8]
count_even_odd(arr)
            

Method 2: Using Recursion

This method counts even and odd numbers using recursion.

def count_even_odd_rec(arr, index=0, even_count=0, odd_count=0):
    if index == len(arr):
        print(f"Even Count: {even_count}, Odd Count: {odd_count}")
        return
    if arr[index] % 2 == 0:
        even_count += 1
    else:
        odd_count += 1
    count_even_odd_rec(arr, index + 1, even_count, odd_count)

arr = [1, 2, 3, 4, 5, 6, 7, 8]
count_even_odd_rec(arr)
            

Method 3: Using List Comprehension

This method uses list comprehension to determine even and odd numbers.

def count_even_odd(arr):
    even_count = len([num for num in arr if num % 2 == 0])
    odd_count = len(arr) - even_count
    print(f"Even Count: {even_count}, Odd Count: {odd_count}")

arr = [1, 2, 3, 4, 5, 6, 7, 8]
count_even_odd(arr)