Inverted Incrementing Triangle Pattern

Understanding the Problem

The goal is to print an inverted triangle pattern where numbers increment sequentially, and each row has a decreasing number of elements.

Pattern Explanation

The pattern follows an inverted triangular structure where numbers increase sequentially from the bottom row to the top row.

7*8*9*10
4*5*6
2*3
1
            

Observations:

• The pattern consists of 4 rows.
• Numbers increment from left to right.
• Each row contains one less element than the previous row.
• Each number is followed by a '*', except the last number in each row.

Algorithm

The pattern follows these steps:

1. Initialize a number counter starting from 1.
2. Determine the total number of rows (N).
3. Calculate the starting number for the first row as (N * (N + 1)) / 2.
4. Loop through rows (from N down to 1).
5. Within each row, loop through columns (up to the current row number).
6. Print the number followed by '*' except for the last number in the row.
7. Increment the number after each print.
8. Move to the next line after printing each row.

Method 1: Using Nested Loops

This method uses two loops to print the pattern.

public class InvertedIncrementingTrianglePattern {
    public static void main(String[] args) {
        int n = 4;  // Number of rows
        int num = (n * (n + 1)) / 2;  // Starting number for the first row

        // Loop to print the inverted incrementing triangle pattern
        for (int i = n; i >= 1; i--) {  // Loop for each row
            for (int j = 1; j <= i; j++) {  // Loop for each column in the current row
                System.out.print(num++);  // Print the current number
                if (j < i) System.out.print("*");  // Print '*' if not the last number in the row
            }
            System.out.println();  // Move to the next line after each row
        }
    }
}
            

Output:

7*8*9*10
4*5*6
2*3
1