Mirrored Incrementing + Inverted Squared Number-Star
Understanding the Problem
The goal is to print a mirrored version of the incrementing and inverted squared number-star pattern.
Pattern Explanation
The pattern follows a grid structure where numbers increase sequentially but are printed in reverse order for each row.
4*3*2*1 12*11*10*9 8*7*6*5 16*15*14*13
Observations:
- The pattern consists of 4 rows and 4 columns.
- Numbers increment from left to right across the grid.
- Each row is printed in reverse order.
- Each number is followed by a '*', except the last number in each row.
Algorithm
The pattern follows these steps:
- Initialize a number counter starting from 1.
- Store values in a 2D array as they increment.
- Loop through rows and print numbers in reverse order.
- Within each row, print numbers right to left with '*'.
- Move to the next line after printing each row.
Method 1: Using Nested Loops
This method first stores values in an array and then prints them in reverse order.
public class MirroredNumberPattern { public static void printPattern(int n) { int[][] arr = new int[n][n]; int num = 1; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { arr[i][j] = num++; } } for (int i = 0; i < n; i++) { for (int j = n - 1; j >= 0; j--) { System.out.print(arr[i][j]); if (j > 0) System.out.print("*"); } System.out.println(); } } public static void main(String[] args) { int size = 4; printPattern(size); } }
Output:
4*3*2*1 12*11*10*9 8*7*6*5 16*15*14*13