Incrementing + Inverted Squared Number-Star (Alternate)
Understanding the Problem
The goal is to print an alternate inverted squared number-star pattern where the row order alternates between normal and reverse.
Pattern Explanation
The pattern follows a grid structure where numbers increase sequentially, but alternate rows appear in reverse order.
1*2*3*4 9*10*11*12 5*6*7*8 13*14*15*16
Observations:
- The pattern consists of 4 rows and 4 columns.
- Numbers increment from left to right across the grid.
- Each number is followed by a '*', except the last number in each row.
- Even-indexed rows are printed normally, while odd-indexed rows are printed in reverse order.
Algorithm
The pattern follows these steps:
- Initialize a number counter starting from 1.
- Store values in a 2D array as they increment.
- Loop through rows, printing normally for even rows and in reverse for odd rows.
- Within each row, print numbers left to right with '*'.
- Move to the next line after printing each row.
Method 1: Using Nested Loops
This method first stores values in an array and then prints them in alternating order.
public class InvertedNumberPattern { public static void printPattern(int n) { int[][] arr = new int[n][n]; int num = 1; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { arr[i][j] = num++; } } for (int i = 0; i < n; i++) { if (i % 2 == 0) { for (int j = 0; j < n; j++) { System.out.print(arr[i][j]); if (j < n - 1) System.out.print("*"); } } else { for (int j = n - 1; j >= 0; j--) { System.out.print(arr[i][j]); if (j > 0) System.out.print("*"); } } System.out.println(); } } public static void main(String[] args) { int size = 4; printPattern(size); } }
Output:
1*2*3*4 9*10*11*12 5*6*7*8 13*14*15*16