Spiral Traversal on a Matrix
Understanding the Problem
The goal is to traverse a matrix in a spiral order.
Method 1: Using Iterative Approach
This method uses an iterative approach to traverse the matrix in spiral order.
#include <iostream>
using namespace std;
void spiralTraversal(int matrix[][100], int rows, int cols) {
int top = 0, bottom = rows - 1, left = 0, right = cols - 1;
while (top <= bottom && left <= right) {
for (int i = left; i <= right; i++) {
cout << matrix[top][i] << " ";
}
top++;
for (int i = top; i <= bottom; i++) {
cout << matrix[i][right] << " ";
}
right--;
if (top <= bottom) {
for (int i = right; i >= left; i--) {
cout << matrix[bottom][i] << " ";
}
bottom--;
}
if (left <= right) {
for (int i = bottom; i >= top; i--) {
cout << matrix[i][left] << " ";
}
left++;
}
}
}
int main() {
int matrix[100][100] = {
{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}
};
int rows = 4, cols = 4;
cout << "Spiral Traversal: ";
spiralTraversal(matrix, rows, cols);
cout << endl;
return 0;
}
Output:
Spiral Traversal: 1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10
Method 2: Using Recursion
This method uses recursion to achieve spiral traversal.
#include <iostream>
using namespace std;
void spiralUtil(int matrix[][100], int top, int bottom, int left, int right) {
if (top > bottom || left > right) return;
for (int i = left; i <= right; i++) {
cout << matrix[top][i] << " ";
}
top++;
for (int i = top; i <= bottom; i++) {
cout << matrix[i][right] << " ";
}
right--;
if (top <= bottom) {
for (int i = right; i >= left; i--) {
cout << matrix[bottom][i] << " ";
}
bottom--;
}
if (left <= right) {
for (int i = bottom; i >= top; i--) {
cout << matrix[i][left] << " ";
}
left++;
}
spiralUtil(matrix, top, bottom, left, right);
}
void spiralTraversal(int matrix[][100], int rows, int cols) {
spiralUtil(matrix, 0, rows - 1, 0, cols - 1);
}
int main() {
int matrix[100][100] = {
{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}
};
int rows = 4, cols = 4;
cout << "Spiral Traversal: ";
spiralTraversal(matrix, rows, cols);
cout << endl;
return 0;
}
Output:
Spiral Traversal: 1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10