Median of 2 Sorted Arrays of Different Sizes
Understanding the Problem
The goal is to find the median of two sorted arrays of different sizes.
Method 1: Simple Merge
This method merges the two arrays and finds the median.
#include <iostream>
using namespace std;
double findMedianSortedArrays(int arr1[], int n1, int arr2[], int n2) {
int merged[n1 + n2];
int i = 0, j = 0, k = 0;
while (i < n1 && j < n2) {
if (arr1[i] < arr2[j]) {
merged[k++] = arr1[i++];
} else {
merged[k++] = arr2[j++];
}
}
while (i < n1) merged[k++] = arr1[i++];
while (j < n2) merged[k++] = arr2[j++];
int total = n1 + n2;
if (total % 2 == 0) {
return (merged[total / 2 - 1] + merged[total / 2]) / 2.0;
} else {
return merged[total / 2];
}
}
int main() {
int arr1[] = {1, 3, 8};
int arr2[] = {7, 9, 10, 11};
int n1 = sizeof(arr1) / sizeof(arr1[0]);
int n2 = sizeof(arr2) / sizeof(arr2[0]);
cout << "Median: " << findMedianSortedArrays(arr1, n1, arr2, n2) << endl;
return 0;
}
Output:
Median: 8.0
Method 2: Binary Search
This method uses binary search to find the median efficiently.
#include <iostream>
#include <climits>
using namespace std;
double findMedianSortedArrays(int arr1[], int n1, int arr2[], int n2) {
if (n1 > n2) {
return findMedianSortedArrays(arr2, n2, arr1, n1); // Ensure n1 <= n2
}
int low = 0, high = n1;
while (low <= high) {
int partition1 = (low + high) / 2;
int partition2 = (n1 + n2 + 1) / 2 - partition1;
int maxLeft1 = (partition1 == 0) ? INT_MIN : arr1[partition1 - 1];
int minRight1 = (partition1 == n1) ? INT_MAX : arr1[partition1];
int maxLeft2 = (partition2 == 0) ? INT_MIN : arr2[partition2 - 1];
int minRight2 = (partition2 == n2) ? INT_MAX : arr2[partition2];
if (maxLeft1 <= minRight2 && maxLeft2 <= minRight1) {
if ((n1 + n2) % 2 == 0) {
return (max(maxLeft1, maxLeft2) + min(minRight1, minRight2)) / 2.0;
} else {
return max(maxLeft1, maxLeft2);
}
} else if (maxLeft1 > minRight2) {
high = partition1 - 1;
} else {
low = partition1 + 1;
}
}
throw invalid_argument("Input arrays are not sorted.");
}
int main() {
int arr1[] = {1, 3, 8};
int arr2[] = {7, 9, 10, 11};
int n1 = sizeof(arr1) / sizeof(arr1[0]);
int n2 = sizeof(arr2) / sizeof(arr2[0]);
cout << "Median: " << findMedianSortedArrays(arr1, n1, arr2, n2) << endl;
return 0;
}
Output:
Median: 8.0